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Question

anonymous · Answer

Yes go on

anonymous · Answer

What is the final concentration of (in M) 16.6 mL iron(III) chloride solution with an initial concentration of 1.343 M which is dilutedÂ with 15.2 mL of solvent? Assume the volumes are additive.

anonymous · Answer

no of milli moles of solute  = (16.6)(1.343)

On dilution, no of milli moles of solute remain constant,  the volume of solution changes

new volume of solution = 16.6 mL+ 15.2 mL = 31.8 mL

Therefore,
final concentration = no of milli moles of solute /  new volume of solution 
                                    = 16.6*1.343 / 31.8
                                    = 0.701 M

anonymous · Answer

I freaking love you :) Thank you so much. Actually makes sense now. 
Also, if i get stuck again, mind if i ask you for help again?

anonymous · Answer

No problem :)