@shivam_bhalla What is the initial concentration (in M) when 18 mL of a iron(III) chloride solution was diluted with 15.2 mL of solvent to a final concentration of 0.639 M? Assume the volumes are additive.

-For the sake of a metal :) -

Question

@shivam_bhalla What is the initial concentration (in M) when 18 mL of a iron(III) chloride solution was diluted with 15.2 mL of solvent to a final concentration of 0.639 M? Assume the volumes are additive. 

-For the sake of a metal :) -

anonymous · Answer

Let x be the intial concentration

no of milli moles = 18(x)

Now new volume= 18+15.2

New concentration = no of milli moles / new volume

WKT new concentration = 0.639

We get

18(x) / (18+15.2)  = 0.639
18(x)=0.639 * 33.2
18(x)=21.215
x = 1.179 milli moles