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Mathematics 7 Online
OpenStudy (anonymous):

Let v1 = (-6,4) and v2 = (-3, 6). Compute the following: c. The scalar projection of v1 onto v2 d. The projection of v1 onto v2 Try not to give me the answer

OpenStudy (anonymous):

just use the formulas

OpenStudy (anonymous):

you should a formula for the prjection of v1 onto v2

OpenStudy (anonymous):

What is the formula, that is what I don't really get.

OpenStudy (anonymous):

do you know what dot product and cross product are?

OpenStudy (anonymous):

@Eureka70 What is the cross product? This is the dot product (x1,y1)*(x2,y2)

OpenStudy (anonymous):

cross product is more complicated multiplication somewhat like dot product, but in this case you don't need it in this case. the projection of one vector onto another is the dot product and gives a scalar. that should be what you need for number 1. For number i think it wants the part of the vector 1 that is in the direction of v2, which is easy to find. the scalar projection should have given you (technically) a value that we use as a coefficient. now if we take this scalar divided by the total length of v2, should give us the fraction of v2 that the projection of v1 covers. so if we multiply this fraction by v2, we should get the projection of v1 on v2.

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