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Mathematics
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Evaluate the integral
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\[\int\limits_{-6}^{9}abs(x^3)*dx\]
Split it into two integrals: \[\int\limits_{-6}^{9}abs(x^3)*dx= \int\limits_{-6}^{0}abs(x^3)*dx+\int\limits_{0}^{9}abs(x^3)*dx\] Get it?
In the first integral, x is always negative or zero; in the second integral, x is always positive or zero. What can you do with the absolute value function using this fact?
So evaluate \[\int\limits_{-6}^{0}-x^3*dx\] and \[\int\limits_{0}^{9}x^3*dx\]
Exactly.
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So I got 7857/4. WebWork says its the right answer. But, how come when I evaluate it with the calculator, it returns the answer 7857/2. Oh never mind. kept reading the calculator wrong
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