Question

find four concecutiveodd integers such that the sum of the second and third is 19 greater than the fourth

Answer 1

x
x+1
x+2
x+3
(x+1) + (x+2) +19 =( x+3)
solve

Answer 2

let X be the first odd integer, can you write the equations?
dont let positron confuse you

Answer 3

sorry
(x+1) + (x+2) =( x+3) +19

Answer 4

still not right... they are consecutive ODD integers

Answer 5

19,20,21,22

Answer 6

20 and 22 are odd?

Answer 7

concecutiveodd i didnt see the space between

Answer 8

he is doing it right, but use X and X+2 and X+4 and X+6 as the numbers

Answer 9

ok thanks

Answer 10

ok i worked it out and still cant get it

Answer 11

what did you come up with?

Answer 12

2x=19

Answer 13

what was the equation you started with?

Answer 14

you got it close, but you had an extra X in there somewhere... or forgot to subtract one of them

Answer 15

x
x+2
x+4
x+6
(x+2) +(x+4) = (x+6) +19
x =19?

Answer 16

x+(x+2) + (x+4)= (x+6 +19

Answer 17

you are adding the first second and third there... it says add the second and third
otherwise, you have it

Answer 18

so what is the correct equasion.. sorry im confused

Answer 19

the second + the third = the fourth + 19
(x+2) + (x+4) = (x+6) + 19

you had it, just had an extra X in there

Answer 20

ok thank you so much:)