Question

intergal (2x-3)5dx can any one help me to solve this problem????

Answer 1

is it
\[\int(2x-3)5dx\]?

Answer 2

is so multiply out and start with
\[\int(10x-15)dx\]

Answer 3

5x^2-15x+c

Answer 4

I'm guessing it's (2x-3)^5 dx

If so the substitution u=2x-3 should work.

Answer 5

i already did that and i also divided 2 in both sides

Answer 6

i came up with 1/2du=dx

Answer 7

Just to clarify, the integral was:

\[\int\limits(2x-3)^{5}dx\]

You substituted u = (2x-3) and dx=1/2 du (which is correct). So you should have

\[\int\limits \frac{1}{2} u^{5}du\]

Answer 8

@beginnersmind : you are right if (2x-5)^5
chose u=2x-5
du=2dx
1/2 du=dx
integral 1/2 u du
1/4 u^2+c
1/4(2x-5)^2+c

Answer 9

edit: du=1/2 dx that is.

Answer 10

is it true buddy?

Answer 11

ummm not really because that's not the answer

Answer 12

yes of course silly me

Answer 13

don't worry about the answer yet. Rick made some errors in calculation. Is the last line in my previous post the same what you got so far?

Answer 14

but you should have
\[\frac{1}{2}\int u^5du=\frac{1}{12}u^6\]

Answer 15

raise the power by one and divide by it
power rule backwards

Answer 16

I think we integrate it well.. so what is the answer?

Answer 17

beginnersmind yes so far your steps are right ? keep on going

Answer 18

f
\[\frac{1}{12}u^6\] substitute back get
\[\frac{1}{12}(2x-5)^6\]

Answer 19

Rizki the answer is (2x-3)^6/12+c

Answer 20

You integrate with respect to u. As satellite said, it's the power rule backwards. Then substitute back (2x-3) for u. Don't forget the integration constant either ;)

Answer 21

i'm sorry, i took u^2 not u^5. Yes, you are right.

Answer 22

beginnersmind can u finish it up plzz

Answer 23

satellite basically did. Just follow his steps, fix the typos and don't forget to add the constant.

Answer 24

yeah always some typos for sure

Answer 25

[1/2\int\limits U^3 dx where that come from ?

Answer 26

\[\frac{1}{2}\int\limits\ u^{3} du \]
anywhere. Did you mean
\[\frac{1}{2}\int\limits\ u^{5} du \]
?

Answer 27

oooh ok i gat it now i was making silly mistake

Answer 28

thank you soo much guys i really appreicate the help

Answer 29

No problem :)