two fair dice are rolled what is the probability that the sum of the dice equal to 5. ( next ? sum of dice is at least 10 or more)
for this we count how many ways to get 5 on two dice? (1,4),(2,3), (3,2), (4,1) four ways out of the total of 36
so your probability is \(\frac{4}{36}=\frac{1}{9}\)
where are you gettiing the 36 from
six possibilities for first die six possibilities for second die counting principle says total ways is \(6\times 6=36\)
While rolling \(n\) dices the sample space is given by \(6^n \)
what first die? im confused
hold on i will send you a table
ok
you see you have 36 possibilities for the two dice to be rolled
ahh ok got it
usually they are described as (1,1) , (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) , (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) , (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) , (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) , (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) , (6,2) (6,3) (6,4) (6,5) (6,6)
so any probability question you have with dice amounts to counting what you want and dividing by 36
so for ten or more, count how many ways you can get ten or more and divide by 36
ok i got 1/6
yeah that'll do it
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