Question

-SOLVE FOR L & W USING SUBSTITUTION & ELIMINATION METHOD:

L×W=1200
π×(W/2π)2×L=600

Answer 1

do you understand what they mean by substitution and elimination method?

Answer 2

rearrange the first equation to solve for L in terms of W.
L=1200/W and plug this expression into the second equation for L and solve

Answer 3

assume the second one is
\[\pi \times (\frac{W}{2\pi})^2\times L=600\] or
\[\frac{W^2}{4\pi}\times L=600\] right?

Answer 4

is it a square, or a two?

Answer 5

2 pie and then it is squared

Answer 6

ok so replacing \(L\) by \(\frac{1200}{W}\) you get
\[\frac{W^2}{4\pi}\times \frac{1200}{W}=600\]

Answer 7

cancel a W and solve the linear equation

Answer 8

you got it from here?

Answer 9

no :( i suck at this one & its a project & i want to pass so i really need help for this one problem please

Answer 10

ok we start with this line
\[\frac{W^2}{4\pi}\times \frac{1200}{W}=600\] cancel and get
\[\frac{W}{4\pi}\times 1200=600\] cancel some more and get
\[300\times \frac{W}{\pi}=600\] multiply by \(\pi\) and divide by 300 to get
\[W=2\pi\]

Answer 11

theres suppose to be a pie sign in front of w/4pie

Answer 12

we canceled that one with one of the ones in the denominator

Answer 13

then how did u get 300?