How would i solve for the sec and cot? if given sec(-pi/6)

Question

anonymous · Answer

you want $\sec(-\frac{\pi}{6})$ find $\cos(-\frac{\pi}{6})$ and take the reciprocal

anonymous · Answer

again find $-\frac{\pi}{6}$ on the unit circle. first coordinate is cosine, reciprocal is secant

anonymous · Answer

so secant,cotangent, and co secant are just reciprocals of sin cos and tangent?

anonymous · Answer

yes

anonymous · Answer

but be careful
secant is the reciprocal of COSINE and cosecant is the reciprocal of sine

anonymous · Answer

how would i solve for this equation ? 2xsquared-6x-9=0?  i tried using the quadratic formula but im coming up with a wrong answer.

anonymous · Answer

$$2x^2-6x-9=0$$ like that ?

anonymous · Answer

$$x=\frac{6\pm\sqrt{6^2-4\times 2\times (-9)}}{2\times 2}$$ whatever that is

anonymous · Answer

yes thanks, before i leave i have ACT's tmmrw any helpful tips?