Question

How would i solve for the sec and cot? if given sec(-pi/6)

Answer 1

you want \(\sec(-\frac{\pi}{6})\) find \(\cos(-\frac{\pi}{6})\) and take the reciprocal

Answer 2

again find \(-\frac{\pi}{6}\) on the unit circle. first coordinate is cosine, reciprocal is secant

Answer 3

so secant,cotangent, and co secant are just reciprocals of sin cos and tangent?

Answer 4

yes

Answer 5

but be careful
secant is the reciprocal of COSINE and cosecant is the reciprocal of sine

Answer 6

how would i solve for this equation ? 2xsquared-6x-9=0? i tried using the quadratic formula but im coming up with a wrong answer.

Answer 7

\[2x^2-6x-9=0\] like that ?

Answer 8

\[x=\frac{6\pm\sqrt{6^2-4\times 2\times (-9)}}{2\times 2}\] whatever that is

Answer 9

yes thanks, before i leave i have ACT's tmmrw any helpful tips?