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how do you solvve log sub4(x-2)- log sub4(x-3)=2
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just assume log sub4(x-2)=a and then solve it
\[\log_{4} [(x -2)/(x -3)] = \log_{4} 16\] So, (x-2)/ (x-3) = 16 or, x-2 = 16x - 48 or, 15x = 46 so, x = 46 / 15
howd u get 46? im confused what do you do fisrt?
yes the answer is right
the answer is 9/2 idk how
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9/2 is may be misprinting. 46/15 is the right answer. Place that value in your original equation (that way you can check your answer)....
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