Cab someone help me understand.... Given: z=z(x,y) find... dz/dy partial if: x^4+3xy^2+5z=sin(z)
alright for this treat everything as a constant except for Y
and if you are differentiating with z you have to put dz/dy and solve for that specific value. Or if you are in multivariable calculus there is a formula which is -Fy/Fz would give your answer
this is basically like implicit differentiation but with 2 variables and if you remember for one variable when you differentiated y you had to put dy/dx so same case applies
@hamza_b23 I love your straight explanation :)
thank you
do i use the formula then or do i differentiate with respect to y and when i get to z i put dz/dy?? sorry implicit differentiate i never understood...
use the formula if you like you would get same answer
so just differentiate with respect to z and y and take the negative quotient?
and do i set the equation to 0 or leave it as is?
if you are finding dz/dy the implicit for that is -Fy/Fz
so take the partial for y over the partial for z with negative as the coefficient
@drifta808 just follow hamza's instruction one step at the time!
( x^4 ) ' = ....
formula looks much easier lol
If it's much easier, why don't you post your solution here?
-(6xy)/5-cos(z)?
Good job, Very close :)
do i leave sin(z) on other side of equal sign? making it -(6xy)/5 = cos(z)
cant be right...
I'm unsure if you mistype or not, just a tiny little bit different? z' = - 6xy/ ( 5z - cosz )
why is it 5z? and not 5? dont u take the derivative?
Since you take dz: d (5z) = 5z dz/dy
that is what i dont understand...
That's how implicit work out!
Pretending take implicit dy/dx with z as y
z now is function of y, just as y is function of x!
ok thanks, gonna have to watch some videos on implicit differentiation.. forget everything about it during multivariable calc
Mee, too! I tend to forget so easily :(
ok, i still dont understand why dz/dy of 5z = 5z(dz/dy) i get the (dz/dy) part but doesnt the chain rule make it just 5 * (dz/dy)
its suppose to be 5*dz/dy
so the answer i put was right? its -6xy/(5-cos(z))?
6xy+5(dz/dy)-cos(z)(dz/dy)=0 dz/dy(5-cos(z))=-6xy dz/dy=-6xy/(5-cos(z)) ??
that the right way to solve this?
yeah your right bro
ah ok thanks alot man... other guy made me really confused there but now i know how to solve these.. thanks!
can u tell me if im doing another problem right?
its all good use the formula its really simple alright if you see dz/dy then its -Fy/Fz
yeah sure
yea i like the formula more too but its nice to know both and this next one is supposed to be a total differential...
f(x1,x2...,xn)=sin(x1+2x2+3x3+...+nxn)
i got cos(x1)+2cos(x2)+...+ncos(xn)
is that all it is?
so what are you doing differentiating that?
it says find the total differential...
O ok one min
and yes bro your absolutely right, but make sure you put in your deltax1 delta x2 ..... delta xn as well
did you get that? so your answer would just be cos(x1)deltax1+2cos(x2)deltax2+...+ncos(xn)deltaxn
delta is the triangle notation
oh sorry got distracted with another problem but ok that makes sense thanks!!! ready to destroy this test now haha
lmao goodluck do me a favourite and give me a medal in every post :P im trying to beat my friend lmao
haha for sure will do!
awesome goodluck
thanks... u 2
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