Question

If heat is lost to the environment during the measurements, then the value of Tf-Ti will be too small... if heat is lost, would the value of c(s) be too large or too small?

Answer 1

c(s)=?

Answer 2

If you're asking about the specific heat capacity, look at the equation for calculating heat.\[Q = m*Cp* \Delta T \]
In solving for C, we get:\[C_p = \frac{Q}{m* \Delta T}\]
If DT is too small, and it's in the denominator of the ratio, what happens to the value of C?

Answer 3

So if DT is small that means it has little effect on C right?

Answer 4

if DT is smaller than it should be, then the denominator will be too small, and the value of C will be too large

Answer 5

if we are talking about the specific heat capacity
then we mast concider that it is constant in most cases....

Answer 6

the accepted value of C is most certainly considered constant, but the calculated value of C based on simple calorimetry is often wrong because of heat lost to the surroundings.

Answer 7

thak you
Now I got the point of the question

Answer 8

Thanks!