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Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius
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CAN WE ASSUME IDEAL GAS??
(a) Kinetic energy is a function of temperature alone: K = (3/2) · kb · T = (3/2) · 1.38065×10⁻²³J/K · 300K
@shivam_bhalla's answer is correct, if we assume it is a ideal gas.
yeap
@shivam_bhalla the formula 3/2 x kb x T which formula is that and what is kb
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kb is boltzmann constant @Rizki_Zhou , yes. We assume it to be deal gas for solving this quetion
See here for more info ---> http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kintem.html
thanks @shivam_bhalla
welcome
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