Question

0<|2x+1|<3 ?
having a problem with the 0...

Answer 1

The answer is \[(-2,-1/2) \cup (-1/2,1)\]

Answer 2

Could it be done individually??

Answer 3

0<|2x+1| & |2x+1|<3

Answer 4

That's the method I did. I know how to handle the |2x+1|<3 but unable to solve the 0<|2x+1|

Answer 5

For this you need 2 equation,
0<|2x+1| , |2x+1|<3
-----------------------
\[0^2<(2x+1)^2\] ,
\[x=-\frac{1}{2}\]
So,
\[x>-\frac{1}{2}\]
\[x<-\frac{1}{2}\]
-------------------------
|2x+1|<3

\[2x+1<\pm(3)\]

2x+1<3

x<1
---------------
2x+1>-3

2x>-4

x>-2
===========
x<1 and x>-2

-2<x<1

Answer 6

Thank you sir :)