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Mathematics 15 Online
OpenStudy (anonymous):

Help!!

OpenStudy (anonymous):

?

OpenStudy (anonymous):

OpenStudy (anonymous):

very simple. :)

OpenStudy (anonymous):

part b?

OpenStudy (anonymous):

its confusing..

OpenStudy (anonymous):

is it okay? \[\theta=800mi/3959mi\] \[\theta=0.2021\times180/\lambda\] 1.16*??

OpenStudy (anonymous):

for part a?

OpenStudy (anonymous):

length of arc = θ * r 800 = θ * 3959 θ = 800 / 3959 = 0.2021 radians = 0.2021 * 360/pi = 23.16 degrees

OpenStudy (anonymous):

isn't it 180/pi for degrees and pi/180 for radian?

OpenStudy (anonymous):

yea - i'm an idiot!! = so its half of 23.16 = 11.58 degrees

OpenStudy (anonymous):

lol its finee...

OpenStudy (anonymous):

now you can do part b by using proportion

OpenStudy (anonymous):

so is it like... theta= 1/3/3959 =8.42x10^-5(180/pi) =0.0048x(1/3600) =1.34x10^-6 sec

OpenStudy (anonymous):

not sure what you've done there i would work it out by (1/3 / 800 ) * 11.58 = 004285 degrees

OpenStudy (anonymous):

= 3600 * 0.004285 = 17.37 seconds

OpenStudy (anonymous):

ohh so i was doing like r=3959, theta=?, s=1/3 so for this part i did it; theata=s/r

OpenStudy (anonymous):

thanks by the way :)

OpenStudy (anonymous):

yw

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