Question

(16x^2-9)/(64x^3-27)*(4x-3)/(4x+3)

Answer 1

what?

Answer 2

it just says to multiply

Answer 3

I would start by factoring out the terms \[16x^2-9\] and \[64x^3-27\]into simple terms. Then you should be able to start canceling them out.
For example, \[16x^2-9\]will break into two terms of the form\[(Ax+B)(Cx+D)\]For that one, what values work for A/B/C/D?

Answer 4

\[(4x-3)^2/(16x^2+12x+)\]

Answer 5

+9

Answer 6

16x^2 -9 4x-3 (4x -3)(4x+3) 4x-3
------------ * ------- = ---------------------- * ------ =
64x^3 -27 4x+3 (4x -3)(16x^2 +12x +9) 4x+3
4x-3
= ---------------
16x^2 +12x +9