If R1 = 6.0 Ω, R2 = 8.0 Ω, R3 = 2.0 Ω, ε1 = 4.0 V, and ε2 = 14 V, what is the power supplied to the circuit by ε1?

Question

anonymous · Answer

attachment

anonymous · Answer

8.0 W
	20 W
	12 W
	4.0 W
	16 W

anonymous · Answer

@experimentx @shivam_bhalla @radar @siddharth18

anonymous · Answer

@myininaya

anonymous · Answer

@laura* @TuringTest

vincent-lyon.fr · Answer

Do you know what the answer should be? I have 8W.

anonymous · Answer

where are u guys where is your choises ??

anonymous · Answer

i get 4 but i think it's wrong ??

anonymous · Answer

@callisto

vincent-lyon.fr · Answer

You must find the values of the currents in each branch.
i left   = 2 A
i right = 3 A

anonymous · Answer

Still not solved??  I will give you the answer in 5 minutes

anonymous · Answer

The answer is 8 W

anonymous · Answer

|dw:1335287391564:dw|
Applying kirchoff's loop rule

Loop ABCFA
$$-E1+(R_1)I+(R_2)I_1=0$$

Loop ABCDEFA
$$-E_1+(R_1)I + (R_3)(I-I_1) - E_2 = 0$$

Substituting the known quantities and solving both equation we get,
$$I=2A$$
$$I_1=-1A$$

Now 
$$Power for E_1 = (E_1)(I) $$
Therefore 
Power for E_1 = 8 W