Question

int (4x-2)/(3(x-1)^2)

Answer 1

I think that's a partial fractions integral. But I will let someone take over here, :-)

Answer 2

I agree...I would use partial fractions

Answer 3

you could also do a simple substitution though

Answer 4

\[u=x-1\]

\[du=dx\]

\[x=u+1\]

Answer 5

\[\int \frac{4x-2}{3(x-1)^2}dx\]

\[\int \frac{4(u+1)-2}{3(u)^2}du\]


expand then integrate term by term