Help! calculus 2.
I got a spiral for #1 and 480 hours for #2. I need help with 3 and 4
480 hours is how many days?
20days
total distance covered = \( \int_{0}^{??} \sqrt{r^2 + \frac{dr}{d\theta}} d\theta \) <-- looks like we have to find cycle first
edit *(dr/dQ)^2
R = 240 000 miles dr/dt = 500 mph time would simply be : R/(dr/dt)
480 hours. Thank you I need help with number 3 and 4
okay ... anything said about the orbit of moon?? elliptical or circular??
no but i think if you go with elliptical its way more complicated..
what do you wanna do??
I have no idea how to do number 3 and 4.... :(
circular or elliptical ... if it is circular, it will be simple. if elliptical it will be complicated.
yes
elliptical??
wouldnt it be too complicated?
let's try for circular first.
it must be something like r = k \( \theta \)
the period of moon is 27 days right?? we need to calculate angular velocity first. \( \frac{d\theta}{dt} = \frac{2\pi}{27*24}\) <--- in hours
\( \theta = \frac{2\pi}{27*24} t\) <--- in hours
okay,
Also dr/dt = 500 mph => r = 500t
and find k?
k =162,000/pi
this is a parametric equation r = 500 \(\theta\)/(2 pi/ 24 * 27)
sorry, it a polar equation ... of spiral
oh, yeah.. haha so r = 500 θ/(2 pi/ 24 * 27) would be the answer for #3?
http://www.wolframalpha.com/input/?i=polar+plot+%282pi%2F%2824*27%29+t+%2C+500+t%29 most likely
http://www.wolframalpha.com/input/?i=polar+plot+r+%3D+500+theta%2F%282pi%2F%2827*24%29%29+
Thank you very much, what about the total distance on #4?
in case our orbit is circular ...
okay ... for that, you have time right??? use that time to find \theta
put that value of \theta on the upper limit of the integral that i posted above. and evaluate the limit ... that will give you the total distance.
what is \theta? just theta?
:'(
θ=2π/(27∗24) t
you know the t from second answer right?? use that t to find \theta and use it ...
I'm sorry, but i do not understand
θ=2π/(27∗24) * 480
|dw:1335307957293:dw| evaluate this /// you will have the distance.
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