Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Help! calculus 2.

OpenStudy (anonymous):

OpenStudy (anonymous):

I got a spiral for #1 and 480 hours for #2. I need help with 3 and 4

OpenStudy (amistre64):

480 hours is how many days?

OpenStudy (anonymous):

20days

OpenStudy (experimentx):

total distance covered = \( \int_{0}^{??} \sqrt{r^2 + \frac{dr}{d\theta}} d\theta \) <-- looks like we have to find cycle first

OpenStudy (experimentx):

edit *(dr/dQ)^2

OpenStudy (experimentx):

R = 240 000 miles dr/dt = 500 mph time would simply be : R/(dr/dt)

OpenStudy (anonymous):

480 hours. Thank you I need help with number 3 and 4

OpenStudy (experimentx):

okay ... anything said about the orbit of moon?? elliptical or circular??

OpenStudy (anonymous):

no but i think if you go with elliptical its way more complicated..

OpenStudy (experimentx):

what do you wanna do??

OpenStudy (anonymous):

I have no idea how to do number 3 and 4.... :(

OpenStudy (experimentx):

circular or elliptical ... if it is circular, it will be simple. if elliptical it will be complicated.

OpenStudy (anonymous):

yes

OpenStudy (experimentx):

elliptical??

OpenStudy (anonymous):

wouldnt it be too complicated?

OpenStudy (experimentx):

let's try for circular first.

OpenStudy (experimentx):

it must be something like r = k \( \theta \)

OpenStudy (experimentx):

the period of moon is 27 days right?? we need to calculate angular velocity first. \( \frac{d\theta}{dt} = \frac{2\pi}{27*24}\) <--- in hours

OpenStudy (experimentx):

\( \theta = \frac{2\pi}{27*24} t\) <--- in hours

OpenStudy (anonymous):

okay,

OpenStudy (experimentx):

Also dr/dt = 500 mph => r = 500t

OpenStudy (anonymous):

and find k?

OpenStudy (anonymous):

k =162,000/pi

OpenStudy (experimentx):

this is a parametric equation r = 500 \(\theta\)/(2 pi/ 24 * 27)

OpenStudy (experimentx):

sorry, it a polar equation ... of spiral

OpenStudy (anonymous):

oh, yeah.. haha so r = 500 θ/(2 pi/ 24 * 27) would be the answer for #3?

OpenStudy (anonymous):

Thank you very much, what about the total distance on #4?

OpenStudy (experimentx):

in case our orbit is circular ...

OpenStudy (experimentx):

okay ... for that, you have time right??? use that time to find \theta

OpenStudy (experimentx):

put that value of \theta on the upper limit of the integral that i posted above. and evaluate the limit ... that will give you the total distance.

OpenStudy (anonymous):

what is \theta? just theta?

OpenStudy (anonymous):

:'(

OpenStudy (experimentx):

θ=2π/(27∗24) t

OpenStudy (experimentx):

you know the t from second answer right?? use that t to find \theta and use it ...

OpenStudy (anonymous):

I'm sorry, but i do not understand

OpenStudy (experimentx):

θ=2π/(27∗24) * 480

OpenStudy (experimentx):

|dw:1335307957293:dw| evaluate this /// you will have the distance.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!