the expression of the square root a/b is always, sometimes, never rational if a and b are integers and b=0

Question

anonymous · Answer

As it was said nobody is allowed to give the answer. Just explain

anonymous · Answer

I would say,  it is Inifnite all the time (i.e undefined)

anonymous · Answer

if b the denominator  = 0 then a/b is indeterminate

anonymous · Answer

a / 0 is meaningless

apoorvk · Answer

Hmm. the no. is irrational if the no. square root is not a perfect square. so, if a and b both are perfect squares in the most simplified form of a/b, then sqrt(a/b) becomes rational, other wise not.

anonymous · Answer

I think @cherry_pie , there is a typing mistake by you.  It should be b not equal to 0

apoorvk · Answer

@cherry_pie  Ofcourse I am guessing that you meant to type 'b' unequal to zero, as a no. isn't defined when the denominator is '0'.

anonymous · Answer

@cherry_pie , if there is a typing mistake and b is not equal to zero, then @apoorvk  answer is perfect :)

anonymous · Answer

yes their was a typing mistake lol

anonymous · Answer

but can you all help me with this problem i just posted