Question

What is the 9th term of the geometric sequence where a1 = -5 and a6 = -5,120?

Answer 1

first find the common ratio
a6 = ar^5 and a1 = -5
so -5120 = 5th root (-5120 / 5) = 5th root 1024 = 4

Answer 2

the 9th term = ( -5)* 4^8

Answer 3

D) -524,288

Answer 4

recall that nth term of a GS is ar^(n-1)

Answer 5

thanks

Answer 6

= -5 * 4 ^ 8

Answer 7

i found the rght answer it was 327680

Answer 8

right

Answer 9

hold on its - 327680

( * -5)