Question

Express as a single logarithm
2lnx-1/2 ln (x^2-1) + 3 ln (x^2 +1)

Answer 1

\[\frac{2\ln (x-1)}{2\ln (x^2-1)}+3\ln (x^2+1)\]

Answer 2

Is that the problem?

Answer 3

no , it is 2lnx ) - (1/2) (x^2-1) + 3ln (x^2+1)

Answer 4

\[2lnx - \frac{1}{2}\ln(x^2-1) + 3\ln(x^2 + 1)\]Is this it?

Answer 5

yes

Answer 6

\[\ln x^2-\ln (x^2-1)^{\frac{1}{2}}+^{}\ln (x^2+1)^3=\ln x^2+\ln (x^2+1)^3-\ln (x^2-1)^{\frac{1}{2}}\]

Answer 7

\[\ln x^2(x^2+1)^3-\ln (x^2-1)^{\frac{1}{2}}=\ln \frac{x^2(x^2+1)^3}{(x^2-1)^{\frac{1}{2}}}\]

Answer 8

i get it , thanks