A question from a contest.
I know that f(b) = 0 then.. :(
The first thing you need to look at, is the term \(f(f(0))=0\). So \(f(b)=0\). This means that \[ab+b=0 \Longrightarrow ab=-b\]Hence, \(a=-1\).
Yeah, my bad. a = -1. As pointed out above.
How do you conclude that if f(b) = 0, ab + b = 0 D:
We conclude that from the definition of the function. \[f(x)=ax+b\]
Now focus on \(f(f(f(4)))=9\) If you expand this out, you get that \[f(f(-4+b))=9\]\[f(-(-4+b)+b)=f(4-b+b)=f(4)=9\]\[-4+b=9\]Hence, you have that \(b=13\).
Now that we have the function, we just have to find that last part.\[f(f(f(f(10))))=f(f(f(-10+13)))=f(f(f(3)))\]\[f(f(f(3)))=f(f(-3+13))=f(f(10))\]\[f(f(10))=f(-10+13)=f(3)\]\[f(3)=-3+13=10\]Thus, we conclude that \(f(f(f(f(10))))=10\)
Ahh, thanks! :DD
You're welcome.
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