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The current I (in amperes) when 100 volts is applied to a circuit is given by I = 3e−2t sin t, where t is the time (in seconds) after the voltage is applied. Approximate the current at t = 0.6 second after the voltage is applied. (Round your answer to two decimal places.)
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I = 3e^(−2t) * sin t,
Hmm. simple enough, just plug in the value of 't' at which the current os required into the equation. t=0.6 seconds. \[\large so, I= 3e^{-2(0.6)}sin(0.6)\] Calculate that, that's your current at time 't = 0.6 seconds'.
My response was .01 but it was wrong.
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