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Definite Integrals anyone?lol
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\[\int\limits_{1}^{e}\left( x- 1/x\right)dx\]
is it\[\int\limits_{1}^{e}\frac{x-1}{x}dx\]?
oh sorry no its x - (1/x)
e^2/2-Ln(e)-1/2+Ln(1)
\[\int\limits\limits_{1}^{e}(x-\frac{1}{x})dx\]\[\int\limits{x-\frac{1}{x}dx}=\int\limits{xdx}-\int\limits{\frac{1}{x}dx}=\frac{x^2}{2}-\ln|x|\] when u evaluate it from 1 to e\[(\frac{e^2}{2}-\ln(e))-(\frac{1}{2}-\ln(1))\]
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\[=\frac{e^2}{2}-1-\frac{1}{2}-0\]
see thats what i got but the book has (e^2 - 3)/2 maybe wrong?
thats the same when u simplify it\[\frac{e^2}{2}-\frac{2}{2}-\frac{1}{2}=\frac{e^2}{2}-\frac{3}{2}=\frac{1}{2}(e^2-3)\]
ohhh ok thank you lalaly
:D:D
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