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lim (lnx(^2))/(x-1) x-->0
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\[\lim_{x \rightarrow 0} (lnx)^2/(x-1)\]
Think about it this way: the limit of the denominator goes to -1 as x goes to 0 and the numerator goes for negative infinity. So, what's the limit?
i miss typed the lim should be approaching 1
Now we have an indetermination of the type 0/0. Apply L'Hopitals rule and voila, you get your answer.
answer is 0.
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And yes, it goes to zero :-)
Follow what @bmp said :)
thanks
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