Question

How do I solve x²-i=0 using the n(th) roots of a complex number in trigonometry?

Answer 1

\[\sqrt[n]{z}=\sqrt[n]{|z|}(cosArg(z)/n+i \sin Arg(z)/n)\]

Answer 2

is x a factor or can I just ignore x then?

Answer 3

x is equal sqrt (i)

Answer 4

so I have standard form sqrt(i)? I dont need to do anything with x?

Answer 5

write it in this way:\[x ^{2}=i \rightarrow x =\sqrt{i}\]
so just use the formula to find sqrt of i

Answer 6

x is what you trying to find....

Answer 7

ok ok I think I got it, the x was throwing me off thanks man

Answer 8

I'm not used to the x being in the equation thanks a lot man

Answer 9

you wellcome

Answer 10

x²=i = e^i pi/2
x = +-e^ i pi/4

Answer 11

thanks