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A box is to be made out of a 8 by 16 piece of cardboard. Squares of equal size will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top. Find the length L, width W, and height H of the resulting box that maximizes the volume. (Assume that W≤L).
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Let a be the side length of the cut-out squares. Then the volume will be: V = (16-2a)(8-2a)*a = 4a^3 - 48a^2 + 128a Differentiating with respect to a gives: 12a^2 - 96a - 128 Put the first differential = 0 and solve for a to find the maximum volume. This gives a = 1.6 L = 12.8, W = 4.8 and H = 1.6
krop, those numbers are wrong
Sorry I made a calculation error. The last two lines should read: This gives a = 1.7 L = 12.6, W = 4.6 and H = 1.7
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