Question

The current I (in amperes) when 100 volts is applied to a circuit is given by
I = 3e^(−2t ) * sin t,
where t is the time (in seconds) after the voltage is applied. Approximate the current at t = 0.6 second after the voltage is applied. (Round your answer to two decimal places.)

Answer 1

\[I=3(e ^{-1.2}\times \sin 0.6)= 3\times 0.17=0.51amps\]