Help with simplifying please :)

How do you get from 1=sqrt(5)secthetax-2ytantheta

to 1= (xsectheta)/2-(ytantheta)/sqrt(5) ??

Question

Help with simplifying please :)

How do you get from 1=sqrt(5)secthetax-2ytantheta

to 1= (xsectheta)/2-(ytantheta)/sqrt(5) ??

anonymous · Answer

not sure
is this 
$$1=\sqrt{5}x\sec(\theta)-2y\tan(\theta)$$

anonymous · Answer

yep exactly

it is in relation to finding the parametric form of a tangent to a hyperbola with P (2sectheta, sqrt5tantheta) if that helps...

anonymous · Answer

no it doesn't help

anonymous · Answer

okay well thanks anyway

anonymous · Answer

looks to me like the left hand side has been devided by $2\sqrt{5}$ but the right hand side has not

anonymous · Answer

If anyone else is able to help, i know the final form of the tangent is $$1=(xsec \theta)/2)-((ytan \theta)/\sqrt{5})$$ but i am having trouble getting in that form...

anonymous · Answer

got my left and right backwards

anonymous · Answer

Yeah- if i could multiply it by a fraction that was equivalent to one it would keep the 1 the same but alter the form of the rhs...just need to figure out that fraction...(not good with fractions)

anonymous · Answer

hmm  the more i look at it, the more it doesn't look the same. one side has been divided, other has not

anonymous · Answer

I must have a mistake in my working.. back to the drawing board! :) thanks for the help