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OpenStudy (saifoo.khan):
Factor the denominators and then find the LCD.
OpenStudy (anonymous):
They don't have a LCD because some of the numbers are prime.
OpenStudy (saifoo.khan):
none of them is prime
OpenStudy (anonymous):
You said i should find the LCD but 11x is only divisible by it self.
OpenStudy (saifoo.khan):
\[\frac{2}{(x+3)(x+5)} + \frac{1}{(x+5)(x+6)}\]Can you solve now?
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OpenStudy (anonymous):
I can try. Okay.
OpenStudy (anonymous):
I took the function you gave me and i took the 2 and divided it into the six leaving them to be the same. So do i go ahead and add them straight across
OpenStudy (saifoo.khan):
o_O
OpenStudy (anonymous):
Is that correct? I got 2/(x+5) (x+3)
OpenStudy (saifoo.khan):
no
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OpenStudy (anonymous):
2/(x+10) (x+9)
OpenStudy (saifoo.khan):
Nope
OpenStudy (anonymous):
What am i doing wrong?
OpenStudy (anonymous):
The function you gave me should i have just continued to add straight across?
OpenStudy (saifoo.khan):
Yes, but u have to take the LCD first
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OpenStudy (anonymous):
Is the LCD is (x+5)
OpenStudy (saifoo.khan):
(x+5)(x+3)(x+6)
OpenStudy (anonymous):
3/(x+5)(x+3)(x+6)
OpenStudy (saifoo.khan):
\[\frac{2(x+6) + 1(x+3)}{(x+5)(x+3)(x+6)}\]
OpenStudy (anonymous):
Now do i cancel them or multiply?
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OpenStudy (saifoo.khan):
Just simplify.
OpenStudy (anonymous):
I got two different answer: The first one i cancel them out i got 3/(x+5)
The second answer i multiplied straight across then cancel out (x+2)/(x+5)
Is any of them correct?
OpenStudy (saifoo.khan):
none
OpenStudy (saifoo.khan):
\[\frac{2x+12+ x + 3}{(x+5)(x+3)(x+6)}\]
\[\frac{3x+15}{(x+5)(x+3)(x+6)}\]
\[\frac{3(x+5)}{(x+5)(x+3)(x+6)}\]
OpenStudy (saifoo.khan):
\[\frac{3}{(x+3)(x+6)}\]
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OpenStudy (anonymous):
I saw how you got it but that's what i got too.
OpenStudy (anonymous):
Thank you for all your help. I really appreciated it.