Question

sqrt{x+5} = sqrt{2x - 1} solve?

Answer 1

just kidding, copied and pasted wrong thing sorry!

Answer 2

square both saide

(dqrt(x+5))^2 = (sqrt(2x-1))^2
x+5=2x-1
x+5-x=2x-1-x
5=x-1
5+1=x-1+1
x=6

Answer 3

\[\sqrt{5x-9}-3=\sqrt{x+4}-2\]

Answer 4

^right one

Answer 5

rigth one is a pain

Answer 6

\[\sqrt{5x-9}-3=\sqrt{x+4}-2\]
\[\sqrt{5x-9}=\sqrt{x+4}+1\]
now square both sides

Answer 7

\[5x-9=(\sqrt{x+4}+1)^2=x+4+1+2\sqrt{x+4}=x+5+\sqrt{x+4}\]

Answer 8

subtract x and 5 from both sides, get
\[4x-14=\sqrt{x+4}\] and then square again!!

Answer 9

sqrt(5x-9)-3 = sqrt(x+4)-2
sqrt(5x-9)-3+3 = sqrt(x+4)-2+3
sqrt(5x-9)=sqrt(x+4)+1

square both sides

5x-9=x+4 +2sqrt(x+4) +1
4x-14 = 2 sqrt (x+4)
2x-7=sqrt(x+4)

square both sides
(2x-7)^2= x+4
4x^2 -28x+49 = x+4
4x^2 -29x + 45=0
(x-5)(4x-9)=0
x=5 or x=9/4

Answer 10

CoCoTsoi has it. i forgot the 2 in front of the \(\sqrt{x+4}\)

Answer 11

satellite, you are good too. :D

Answer 12

don't forget to check your answers, because when you square you could introduce an extraneous solution

Answer 13

what's an extraneous solution?

Answer 14

and I don't get your 3rd post, satellite73