I need help . 12. A certain object has an initial height of 40 feet and a maximum height of 500 feet. Find the height
equation, s(t) = -16t2 + v0t + s0, for the object. (Hint: With a vertex of (h,k), the height equation can be
written as s(t) = -16(t -h)² + k.

Question

I need help . 12. A certain object has an initial height of 40 feet and a maximum height of 500 feet. Find the height 
equation, s(t) = -16t2 + v0t + s0, for the object. (Hint: With a vertex of (h,k), the height equation can be 
written as s(t) = -16(t -h)² + k.

anonymous · Answer

|dw:1335325745232:dw|
y-coord.  = 500

 s(t) = -16(t -h)² + 500
initial height is 40
therefore,
 s(0)=40 (intial i.e. t=0)
-16(0-h)² + 500= 40
-16h^2 = -460
h^2 = 115/4
h=5.36

therefore, the equation is 
 s(t) = -16(t -(sqrt(115/4)))² + 500
then expand it.