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3^(x+4)=7^(x-1)
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HINT: ______ take log to both sides ,so that the power will get down
\[ 3^{(x+4)}=7^{(x-1)} \implies (x+4) \log 3 = (x-1) \log 7 \] \[ \implies x(\log 3 -\log 7)= -(\log7+\log 3^4)\]
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i need more help .
\[ \implies x = \frac{ -(\log7+\log 3^4)}{(\log 3 -\log 7)} \] You can simplify further using the logarithm rules.
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\(\log a + \log b = \log ab \) \(\log a - \log b = \log \frac ab \) \(\log_a b = \frac {\log a} { \log b } \)
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