Question

The potential difference across two capacitors in series is 210. V. the capacitances are C1=3400. mf. and C2=3940 mf.
a) what is the capacitance of this pair of capacitors ?
Ceq=............ mf.

Answer 1

it tells me that the answer is wrong !

Answer 2

sorry i misread it .....working on it

Answer 3

:D ThnQQ !

Answer 4

is it 1825.06 mf?

Answer 5

it tells me that it's wrong answer ! again ! =/

Answer 6

have you provided the correct details? 1/c1 +1/c2

Answer 7

thats how we calculate capacitance for 2 capacitors in series.

Answer 8

(c1*c2)/(c1+c2)

Answer 9

thats correct too product/sum

1/c1 +1/c2 = c1*c2/c1+c2 ;)

Answer 10

i didn't get it actually !

Answer 11

whats the correct answer?

Answer 12

it didnt tell me !!

Answer 13

it is telling me try again !

Answer 14

try this 7340

Answer 15

7340 it's right :D
b) what is the charge on each capacitor ?
q1=..........C
q2=..........C
c) what is the potential difference across each capacitor ?
V1=..........V
V2=.........V
d) what is the total energy stored by the capacitors ?
U=........J

Answer 16

okay so i did this.

firstly i just calculated the charge on each capacitor

for C1

Q=CV

Q=.714

for C2

Q=CV

Q=.8274

Total Q = Q1 + Q2
= 1.5414

Now we have total Q put it in equation Q=CV
1.5414=C*210
C=7340mF

Answer 17

ThnQQ !!

Answer 18

Energy = 1/2 *C*V^2
=1/2 * 7340mf*210^2
=161.847J