Question

okay so this is so complicated, i dont even know where to start. Are the complex fractions the quantity x¨Csquared minus x minus 20 over 4 all over the quantity x minus 5 over 10 and the quantity x¨Csquared minus x minus 20 over x minus 5 all over the quantity 4 over 10 equivalent? Simplify each, and then explain why or why not.

Answer 1

simplify it !!

Answer 2

both are same

Answer 3

the Common factor would be 5

Answer 4

?

Answer 5

means both the question are same
\[{10\times(x^2 - x- 20)}\over{4\times(x-5)}\]
\[={{{5\times(x^2-5x+4x-20)}}\over{2\times(x-5)}}\]
\[={{{5\times((x-5)(x+4x))}\over{2\times(x-5)}}}\]
\[={{{5\times(x+4x)}\over{2}}}\]

Answer 6

when you are dividing fractions, flip and multiply!
to say it technically "dividing by a fraction is the same as multiplying by its reciprocal"

Answer 7

here is the rule in general\[\huge \frac{a\over b}{c\over d}=\frac ab\cdot\frac dc=\frac{ad}{bc}\]

Answer 8

so your problem becomes\[\huge \frac{x^2-x-20\over4}{x-5\over10}={x^2-x-20\over4}\cdot\frac{10}{x-5}\]