Question

A farmer is taking her eggs to the market in her cart, but she hits a pothole, which knocks over all the containers of eggs. Though she herself is unhurt, every egg is broken. SO=o she goes to her insurance agent, who asks her how many eggs she had. She says she does'nt know, but she remembers some things from various ways she tried packing the eggs. She knows that whn she put the eggs in groups of three, there was also one egg left over. The same thing happend when she put them in groups of four, groups 0f five , or group of 6. But when she put them in groups of seven, she ended up with compl

Answer 1

Can you finish the question?

Answer 2

groups of seven with no eggs leftover

Answer 3

what can the farmer figure out from this information about how man eggs she had?
Is there more than one possibility.

Answer 4

its too hard!!!!! D;

Answer 5

-_-'

Answer 6

@amistre64 ban please?

Answer 7

fan or ban?

Answer 8

lol and there is no more than one possibility

Answer 9

ask someone else for the answer. ban or fan??

Answer 10

Drd, please dont participate in a question if you have no intention of actually helping out ....

Answer 11

thanks amistre64

Answer 12

As for the question itself, that is alot to try to parse thru ... but i think the assumption can be that the eggs are a count that is a multiple of 7

Answer 13

I was going to help

Answer 14

but exclude the multiples of the outher counts from it

Answer 15

my friend said this............


since there is one left over for groups of 3, 5, 6, find their common multiples and add one to get a multiple of 7.
common multiples: 30, 60,90 .... there it is: 91 works.

Answer 16

sounds very number theory like to me

Answer 17

does that solution include the 4 grouping?

Answer 18

91/4 = 22 R 3

Answer 19

i think it does

Answer 20

the concept might work, but i dont think 91 will

Answer 21

thanks again amistreo64 :)

Answer 22

youre welcome :)

Answer 23

Did you understand that 91 is not the solution. You were on the right track, just did not carry it far enough. I believe the farmer could of had 721 eggs.

Answer 24

Eggs are usually sold by the dozen, and you would assume it would a multiple of 12 lol

Answer 25

hod did you solv it?

Answer 26

Like your friend suggested 3 X 4 X 5 X 6 = 360 add 1 and you get 361, in order to be evenly divided by 7 (no remainder) I added 360 to 361 and got 721 which will work.