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x/4-2/3=x+5
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\[\frac{x}{\frac{4-2}{3}}=x+5\] Is this right?
no (x)(4)-(2)(3)=x+5
so you're multiplying everything? that is, no division?
Or is it like \[{x \over 4} - {2 \over 3} = x+5\]
yes like that
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-68 = 9x, so x= - 68/9
how do you get 68
Hmm, this is what I would do: Find the least common multiple (aka least common denominator) of the entire equation. Then multiply this number to each term, even on the right side of the equation. Solving for x would probably look a lot easier by then.
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