Question

If y=(5/2)(e^(x/5)+e^(-x/5)), then prove that y"=y/25?

Answer 1

differentiate'em twice ... and see what you get

Answer 2

\[y=5/2 (e^{x/5}+e^{-x/5})\]

Answer 3

\[y'=1/2e ^{-x/5}(e ^{x/5}-1)\]

Answer 4

you don't have to take out that e's .... leave it as it is.

Answer 5

\[y"=1/10e ^{-x/5}(e^{x/5}+1)\]