Mathematics
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OpenStudy (anonymous):
can anyone help me with this question please..
add <4,60> and <2,315> and express the result in polar form
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OpenStudy (anonymous):
add a+a and b+b
OpenStudy (anonymous):
you mean a1 and b1 like that?
OpenStudy (anonymous):
yeah <a1+a2, b1+b2>
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
then you have to find the angle and the ray
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OpenStudy (anonymous):
polar form is <r, theta>
OpenStudy (anonymous):
how much will you get when you add those
OpenStudy (anonymous):
<6, 375>
OpenStudy (anonymous):
thats what i got
OpenStudy (anonymous):
whats the next step
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OpenStudy (anonymous):
r=√a²+b² you know that right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok find r
OpenStudy (anonymous):
how much you got?
OpenStudy (anonymous):
what did you get?
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OpenStudy (anonymous):
i got 375.04
OpenStudy (anonymous):
is that right?
OpenStudy (anonymous):
if you can use decimal form, can you?
OpenStudy (anonymous):
375.0479959
OpenStudy (anonymous):
may b not
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OpenStudy (anonymous):
ok do you know how to find theta?
OpenStudy (anonymous):
well its a prime number
OpenStudy (anonymous):
how not to write in decimal form?
OpenStudy (anonymous):
√140661, cant be factored any more
OpenStudy (anonymous):
oo yea
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OpenStudy (anonymous):
hang on i think it can
OpenStudy (anonymous):
how can we find theta?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
do you know how to simplify square roots?
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
but not much
OpenStudy (anonymous):
try to divde by things that are factorable under the square root
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
the lowest its going to go is 3√15629
OpenStudy (anonymous):
i got that too
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OpenStudy (anonymous):
now to find theta you have to remember tanθ=b/a
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so place b/a and find the arctan
OpenStudy (anonymous):
ok i got 62.5
OpenStudy (anonymous):
so polar form = <3√15629, 62.5°>, does this look right?
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OpenStudy (anonymous):
mmm yea..
OpenStudy (anonymous):
thanks a lot,, appreciate your help
OpenStudy (anonymous):
no problem