Question

∫ x/(x^2-4)

Answer 1

you got to do this by partial fractionss

Answer 2

Can you please show the step work for solving this. I believe you can use u-substitution

Answer 3

\[ 1/2 \ln(x^2-4)+c\]

Answer 4

yes you can...let u = x^2 - 4

du = 2xdx
xdx = du/2

\(\LARGE \frac{1}{2} \int \frac{du}{u}\)

Answer 5

\(\LARGE \frac{1}{2} \ln u = \frac{1}{2} \ln (x^2 - 4)\)

Answer 6

+ C

Answer 7

others prefer the answer..

\(\ln \sqrt{x^2 -4} + C\)