how to solve 3 radical 75 plus 2 radical 5 and the solution? (operations with radical expressions)

Question

anonymous · Answer

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anonymous · Answer

hmm ok i have think, that's new, wait a sec haha

anonymous · Answer

haha its cool. its kind of a confusing topic lol

anonymous · Answer

it's not like this is it?
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anonymous · Answer

$$3\sqrt{75}+2\sqrt{5}$$

anonymous · Answer

not possible!

anonymous · Answer

already done!

anonymous · Answer

yea it is but its just confusing. algebra is not fun. at least to my stupid no-math brain lol

anonymous · Answer

wait, did you get it?

anonymous · Answer

is that how the assignment was given?

anonymous · Answer

wait, what? im kinda confused lol

anonymous · Answer

$$75=25\times 3$$ so 
$$\sqrt{75}=\sqrt{25\times 3}=\sqrt{25}\times \sqrt{3}=5\sqrt{3}$$

anonymous · Answer

but you cannot combine it with $2\sqrt{5}$ because they are not like terms, so your answer is probably $15\sqrt{3}+2\sqrt{5}$

anonymous · Answer

ah of course

anonymous · Answer

unless you meant to write the cubed root, as in $\sqrt[3]{75}$ in which case you can do nothing

anonymous · Answer

no no i think the answer is just the above one before Bounty said "ah of course"

anonymous · Answer

yeah

anonymous · Answer

thanks guys!