Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

the beginning of 1975 the population of a country was 40 million and growing at a rate of 3% per year. Assume that the growth is exponential. Estimate the population of the country at the beginning of the year 2010

OpenStudy (anonymous):

of course 80 million

OpenStudy (anonymous):

im sorry and how did you get this?

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

This can be taken as a geometric progression where the population at any given year is given by \[ar ^{n-1}\] where a is starting population and 'r' in this case is 1.03 as the population is increasing. Now count the years, from 1975 to 2010, 35 years. So you use formula population = \[40000000\times1.03^{35}\] population approx 112 million

OpenStudy (anonymous):

i got 83751117 how did you get 112 mil?

OpenStudy (anonymous):

how did you get that? Because I've used exponential population growth method and geometric progression and got the same answer

OpenStudy (anonymous):

ok i rechecked it ant got 1.05 and the answer was 135mil

OpenStudy (anonymous):

ok let me g through it again. two mins :)

OpenStudy (anonymous):

40000000*1.05^24 was 129003997.7

OpenStudy (anonymous):

it can't be 1.05 as you gave the growth rate to be 3% If it is 5%, then you get 40(1.05)^35 = 220 million Check your question again. You get 135 million if the growth rate is 5% and the time period is 1975 to 2000

OpenStudy (anonymous):

yeah the years are 1975 to 2010

OpenStudy (anonymous):

nm

OpenStudy (anonymous):

can you help me with this one?

OpenStudy (anonymous):

If the population of bacteria doubles in 4 hours how long will it take for it to triple its original size

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!