A box is constructed of two different types of metal. The metal for the top and bottom which are both square costs $5 per square foot and metal for the sides costs $6 per square ft find the dimensions that minimize cost if the box has a v=25ft.
The surface area of a six-sided box = 2 HW + 2HD + 2WD where H=height of box, D=depth of box, W=width of box. But because the width and depth are the same (the top and bottom are square) then Surface area = 4 HW +2 W^2
hmmmmm.......what is v? Is that the width of the box? the height?
|dw:1335412010307:dw| so since the base and top are both squares, their lenght n width will be same which we let to be as x. we let the height be y . The are of top n bottom will be 2x^2 and that of the 4 remaining are 4xy, so total are of box will be 2x^2 + 4xy. The cost will thus be 5(2x^2) + 6(4xy)
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