Question

find solutions in interval [0,2pie) for csc^2x=cotx+1

Answer 1

x=pi/8

Answer 2

thats not a choice.
do you want me to list the choices ?

Answer 3

yeah..

Answer 4

sorry pi/4

Answer 5

or 45 degrees

Answer 6

I mean solution is cosx=sinx

Answer 7

A. pie/4 , 3pie/4 , 4pie/3
B. pie/2 , 3pie/2
C. 0 , pie/2 , pie , 3pie/2
D. pie/4 , pie/2 , 5pie/4 , 3pie/2
E. pie/4 , 4pie/3 , 11pie/6

Answer 8

use the identity\[\csc^2 x = 1 + \cot^2 x\]\[\csc^2 x = \cot x + 1\]\[1 + \cot^2 x = \cot x + 1\]\[\cot^2 x - \cot x = 0\]\[\left( \cot x \right)\left( \cot x - 1 \right) = 0\]can you continue after this ?

Answer 9

not really. i don't understand how that gets any of the answers

Answer 10

\[\cot x = 0\]or \[\cot x - 1 = 0\]\[\cot x = 1\]find all values of x within the interval [0,2π) that satisfies cot x = 0 or cot x = 1

Answer 11

OHH thanks !!