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Mathematics 6 Online
OpenStudy (anonymous):

x* ln(3)=2-x *ln(2)

OpenStudy (anonymous):

don't forget that \(\ln(3)\) and \(\ln(2)\) are just numbers

OpenStudy (anonymous):

so you get \[x\ln(3)+x\ln(2)=2\]by adding to both sides, then factor as \[x(\ln(3)+\ln(2))=2\] and finally \[x=\frac{2}{\ln(3)+\ln(2)}\]

OpenStudy (anonymous):

you can write \[x=\frac{2}{\ln(6)}\] if you like since \(\ln(a)+\ln(b)=\ln(ab)\)

OpenStudy (anonymous):

ok I was thrown by the x in front... thanks

OpenStudy (anonymous):

yw

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