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Mathematics 8 Online
OpenStudy (kainui):

How can I tell if this series converges or not by the root test?

OpenStudy (kainui):

\[\sum_{k=1}^{\infty} (1+3/k)^{k^2}\]

OpenStudy (kainui):

Can I apply the root test twice, since if that limit converges, the other one will converge too?

OpenStudy (anonymous):

remember that \[a _{k=1}/a _{k}\]

OpenStudy (anonymous):

k+1****

OpenStudy (kainui):

Yeah, I guess for some reason I was thinking I needed to get it into a form without an exponent to see if it converged or not, but really all I have to do is evaluate the limit... right?

OpenStudy (anonymous):

well it conv. \[\left| r \right|<1\]

OpenStudy (anonymous):

The sum diverges. And now that I think of it, I think I was right.

OpenStudy (anonymous):

Let me look into my Calc book.

OpenStudy (anonymous):

That's correct, if the limit goes to infinity, the series diverges also.

OpenStudy (anonymous):

you have to solve then take the lim if the answer is less then 1 then conv.

OpenStudy (anonymous):

So yeah, you only need to apply it once.

OpenStudy (kainui):

Thanks guys, helped a bunch.

OpenStudy (anonymous):

No problem :-)

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