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Mathematics 12 Online
OpenStudy (anonymous):

Find the exact value of the area under one arch of the curve y(t) = V0sin(wt). Assume V0 and w are positive constants. You can use V_0 for V0. Note - V is upper case here

OpenStudy (inkyvoyd):

y=asin(wt) Now we find the period, and we know that half a period is an arch.

OpenStudy (inkyvoyd):

The period of y=sin(t) is 2pi, so what would y=sin(wt) be?

OpenStudy (inkyvoyd):

@Ldaniel

OpenStudy (anonymous):

t/w

OpenStudy (anonymous):

2pi/w

OpenStudy (inkyvoyd):

Alright, then we know that we want to integrate the function from 0 to pi/w, right?

OpenStudy (inkyvoyd):

@Ldaniel

OpenStudy (anonymous):

yes\

OpenStudy (inkyvoyd):

So, we are looking for \[\int\limits_{0}^{pi/w}asin(wt)dt\]

OpenStudy (inkyvoyd):

where a and w are both constants.

OpenStudy (inkyvoyd):

take out the a, and it becomes \[a \int\limits_{0}^{pi/w}\sin(wt) dt\]

OpenStudy (anonymous):

|dw:1335426994623:dw|

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