Question

a man wishes to enclose 2 separate lots with 300 yrds of fencing, one lot is a square n the other a rectangle twice as long as its wide. determine the dimensions of each lot if total area to be enclosed is a minimum. use the quadratic relation to hsow ur work

Answer 1

a fig. would help!

Answer 2

iam sorry?!!

Answer 3

do u know the formule!

Answer 4

plz if u r not going to answer then dont bother wasting my time n urs. THNK U

Answer 5

@Rohangrr UR TECHNICALLY A FIG!

Answer 6

@khadija UR jack of all trade but master of none!
seriously u r the biggest joker out here! lol! ha hah ha

Answer 7

@Rohangrr u've proved me right! u r an idiot of life! this is wat u call NO LIFE! am sorry:p jokes on u!

Answer 8

dont flirt the BIGGEST JOKER OS!! Sorry AH! sorry:p jokes on JOKER @khadija

Answer 9

Hello guys, Please be respectful.

Answer 10

OK tht was just simply stupid!! n plz if u dont wish to answer u can leave no1 asked u!! those who want to will help nn a fool like u wud waste time

Answer 11

hey in this case let us assume length of one side of square be x
therefore total fencing for square would be 4x
while a rectangle having its length double of of its width
hey @khadija is there any relation between square and rectangle

Answer 12

@sheg NOPE:(

Answer 13

ok

Answer 14

i feel it would be 300 yards each

Answer 15

nope..

Answer 16

or width should be equal to side of the square

Answer 17

??? u r finding the dimensions

Answer 18

I have a solution:
The square has sides of 35.29 yards
The rectangle has short sides 26.47 yards and long sides 52.94 yards.
Do you want me to show my workings?

Answer 19

@kropot72 yes please, tht wud be great!! n thnk u=D ur help is greatly appreciated

Answer 20

@kropot72 can u help me with 2 moreas ell. If u can =D thnnkk u

Answer 21

Let length of side of square = s
Let length of short side of rectangle = r
4s + 2r + 4r = 300
4s = 300 - 6r
s = 75 -1.5r

Area of square = r^2 = (75 - 1.5r)^2
Area of rectangle = 2r^2
Let total area = A
A = (75 - 1.5r)^2 + 2r^2 = 4.25r^2 - 225r + 5625
Differentiating A w.r.t. r:
dA/dr = 8.5r - 225
Put the result of differentiating equal to zero and solve to find the minimumvalue of A:
8.5r - 225 = 0
8.5r = 225
r = 26.47 yards
Substituting for r gives:
s = 75 - (26.47 * 1.5) = 35.29 yards
The square has sides of 35.29 yards
The rectangle has short sides 26.47 yards and long sides 52.94 yards.

Answer 22

ohh nice!! THNNNKKKK UUUUU SO MUCHHH!! tht was really helpfull :D thnx;)

Answer 23

You're welcome. Sorry I can't help with more. Must get some sleep!!!

Answer 24

aww no its ok dw:) ths was awesome =D go get ur rest!!

Answer 25

Rohangrr, do not call other users jokers and insult them. It's against our Code of Conduct. Thanks!