For the isomerization reaction:
butane ⇌ isobutane
Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 5.0. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium?

Question

For the isomerization reaction: 
butane ⇌ isobutane
Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 5.0. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium?

mos1635 · Answer

butane ⇌ isobutane
Po                0
-P                +P
Po-P             P

Kp=25
P/Po-P=25
P=25*(Po-P)
P=(25/26)*Po
P=125/26 atm
so..........